10(1/2x-2)-5=3(x-6)+1

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Solution for 10(1/2x-2)-5=3(x-6)+1 equation: 



10(1/2x-2)-5=3(x-6)+1

We move all terms to the left:

10(1/2x-2)-5-(3(x-6)+1)=0



Domain of the equation: 2x-2)!=0

x∈R



We multiply parentheses

10x-(3(x-6)+1)-20-5=0



We calculate terms in parentheses: -(3(x-6)+1), so:

3(x-6)+1

We multiply parentheses

3x-18+1

We add all the numbers together, and all the variables

3x-17

Back to the equation:

-(3x-17)



We add all the numbers together, and all the variables

10x-(3x-17)-25=0

We get rid of parentheses

10x-3x+17-25=0

We add all the numbers together, and all the variables

7x-8=0

We move all terms containing x to the left, all other terms to the right

7x=8

x=8/7

x=1+1/7

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