10(1/5x+2)=10(1/5x+1

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Solution for 10(1/5x+2)=10(1/5x+1 equation: 



10(1/5x+2)=10(1/5x+1

We move all terms to the left:

10(1/5x+2)-(10(1/5x+1)=0



Domain of the equation: 5x+2)!=0

x∈R





Domain of the equation: 5x+1)!=0

x∈R



We multiply parentheses

10x-(10(1/5x+1)+20=0

We multiply all the terms by the denominator


10x*5x+1)+20-(10(1=0

We add all the numbers together, and all the variables

10x*5x=0

Wy multiply elements

50x^2=0

a = 50; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·50·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{100}=0$

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