10(11a-10)-10a=-(4a-4)

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Solution for 10(11a-10)-10a=-(4a-4) equation: 



10(11a-10)-10a=-(4a-4)

We move all terms to the left:

10(11a-10)-10a-(-(4a-4))=0

We add all the numbers together, and all the variables

-10a+10(11a-10)-(-(4a-4))=0

We multiply parentheses

-10a+110a-(-(4a-4))-100=0



We calculate terms in parentheses: -(-(4a-4)), so:

-(4a-4)

We get rid of parentheses

-4a+4

Back to the equation:

-(-4a+4)



We add all the numbers together, and all the variables

100a-(-4a+4)-100=0

We get rid of parentheses

100a+4a-4-100=0

We add all the numbers together, and all the variables

104a-104=0

We move all terms containing a to the left, all other terms to the right

104a=104

a=104/104

a=1

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