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10(11v-3)-11=6v+63
We move all terms to the left:
10(11v-3)-11-(6v+63)=0
We multiply parentheses
110v-(6v+63)-30-11=0
We get rid of parentheses
110v-6v-63-30-11=0
We add all the numbers together, and all the variables
104v-104=0
We move all terms containing v to the left, all other terms to the right
104v=104
v=104/104
v=1
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