10(12x+10x)+11(4-2x)=398

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Solution for 10(12x+10x)+11(4-2x)=398 equation: 



10(12x+10x)+11(4-2x)=398

We move all terms to the left:

10(12x+10x)+11(4-2x)-(398)=0

We add all the numbers together, and all the variables

10(+22x)+11(-2x+4)-398=0

We multiply parentheses

220x-22x+44-398=0

We add all the numbers together, and all the variables

198x-354=0

We move all terms containing x to the left, all other terms to the right

198x=354

x=354/198

x=1+26/33

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