10(18-8/5x)+2x=10x+6(18-8/5x)

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Solution for 10(18-8/5x)+2x=10x+6(18-8/5x) equation: 



10(18-8/5x)+2x=10x+6(18-8/5x)

We move all terms to the left:

10(18-8/5x)+2x-(10x+6(18-8/5x))=0



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

10(-8/5x+18)+2x-(10x+6(-8/5x+18))=0

We add all the numbers together, and all the variables

2x+10(-8/5x+18)-(10x+6(-8/5x+18))=0

We multiply parentheses

2x-80x-(10x+6(-8/5x+18))+180=0

We multiply all the terms by the denominator


2x*5x+18))-80x*5x+18))-(10x+6(-8+180*5x+18))=0

We add all the numbers together, and all the variables

2x*5x+18))-80x*5x+18))-(10x+6(180*5x+10))=0

Wy multiply elements

10x^2+18))-80x*5x+18))-(10x+6(180*5x+10))=0

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