10(2+0.2y)-2y=16

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Solution for 10(2+0.2y)-2y=16 equation: 



10(2+0.2y)-2y=16

We move all terms to the left:

10(2+0.2y)-2y-(16)=0

We add all the numbers together, and all the variables

10(0.2y+2)-2y-16=0

We add all the numbers together, and all the variables

-2y+10(0.2y+2)-16=0

We multiply parentheses

-2y+0y+20-16=0

We add all the numbers together, and all the variables

-1y+4=0

We move all terms containing y to the left, all other terms to the right

-y=-4

y=-4/-1

y=+4

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