10(2+1x)=15(1x+-1)+5

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Solution for 10(2+1x)=15(1x+-1)+5 equation: 



10(2+1x)=15(1x+-1)+5

We move all terms to the left:

10(2+1x)-(15(1x+-1)+5)=0

We add all the numbers together, and all the variables

10(x+2)-(15(x-1)+5)=0

We multiply parentheses

10x-(15(x-1)+5)+20=0



We calculate terms in parentheses: -(15(x-1)+5), so:

15(x-1)+5

We multiply parentheses

15x-15+5

We add all the numbers together, and all the variables

15x-10

Back to the equation:

-(15x-10)



We get rid of parentheses

10x-15x+10+20=0

We add all the numbers together, and all the variables

-5x+30=0

We move all terms containing x to the left, all other terms to the right

-5x=-30

x=-30/-5

x=+6

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