10(2+3x)=-80

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Solution for 10(2+3x)=-80 equation: 



10(2+3x)=-80

We move all terms to the left:

10(2+3x)-(-80)=0

We add all the numbers together, and all the variables

10(3x+2)-(-80)=0

We add all the numbers together, and all the variables

10(3x+2)+80=0

We multiply parentheses

30x+20+80=0

We add all the numbers together, and all the variables

30x+100=0

We move all terms containing x to the left, all other terms to the right

30x=-100

x=-100/30

x=-3+1/3

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