10(2+4)-3(2-4)=3(2-2)+3(2-1)

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Solution for 10(2+4)-3(2-4)=3(2-2)+3(2-1) equation: 


Simplifying
10(2 + 4) + -3(2 + -4) = 3(2 + -2) + 3(2 + -1)

Combine like terms: 2 + 4 = 6
10(6) + -3(2 + -4) = 3(2 + -2) + 3(2 + -1)

Multiply 10 * 6
60 + -3(2 + -4) = 3(2 + -2) + 3(2 + -1)

Combine like terms: 2 + -4 = -2
60 + -3(-2) = 3(2 + -2) + 3(2 + -1)

Multiply -3 * -2
60 + 6 = 3(2 + -2) + 3(2 + -1)

Combine like terms: 60 + 6 = 66
66 = 3(2 + -2) + 3(2 + -1)

Combine like terms: 2 + -2 = 0
66 = 3(0) + 3(2 + -1)

Multiply 3 * 0
66 = 0 + 3(2 + -1)

Anything times zero is zero.
66 = 0 + 3(2 + -1)

Combine like terms: 2 + -1 = 1
66 = 0 + 3(1)

Multiply 3 * 1
66 = 0 + 3

Combine like terms: 0 + 3 = 3
66 = 3

Solving
66 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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