10(2+a)=15(a-1)+5

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Solution for 10(2+a)=15(a-1)+5 equation: 



10(2+a)=15(a-1)+5

We move all terms to the left:

10(2+a)-(15(a-1)+5)=0

We add all the numbers together, and all the variables

10(a+2)-(15(a-1)+5)=0

We multiply parentheses

10a-(15(a-1)+5)+20=0



We calculate terms in parentheses: -(15(a-1)+5), so:

15(a-1)+5

We multiply parentheses

15a-15+5

We add all the numbers together, and all the variables

15a-10

Back to the equation:

-(15a-10)



We get rid of parentheses

10a-15a+10+20=0

We add all the numbers together, and all the variables

-5a+30=0

We move all terms containing a to the left, all other terms to the right

-5a=-30

a=-30/-5

a=+6

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