10(2/5+0.5x)=4x

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Solution for 10(2/5+0.5x)=4x equation:



10(2/5+0.5x)=4x
We move all terms to the left:
10(2/5+0.5x)-(4x)=0
Domain of the equation: 5+0.5x)!=0
We move all terms containing x to the left, all other terms to the right
0.5x)!=-5
x!=-5/1
x!=-5
x∈R
We add all the numbers together, and all the variables
10(+0.5x+2/5)-4x=0
We add all the numbers together, and all the variables
-4x+10(+0.5x+2/5)=0
We multiply parentheses
-4x+0x+2/5*10=0
We multiply all the terms by the denominator
-4x*5*10+0x*5*10+2=0
Wy multiply elements
-200x*1+0x*1+2=0
Wy multiply elements
-200x+0x+2=0
We add all the numbers together, and all the variables
-199x+2=0
We move all terms containing x to the left, all other terms to the right
-199x=-2
x=-2/-199
x=2/199

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