10(20-y)+200y=280

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Solution for 10(20-y)+200y=280 equation: 



10(20-y)+200y=280

We move all terms to the left:

10(20-y)+200y-(280)=0

We add all the numbers together, and all the variables

10(-1y+20)+200y-280=0

We add all the numbers together, and all the variables

200y+10(-1y+20)-280=0

We multiply parentheses

200y-10y+200-280=0

We add all the numbers together, and all the variables

190y-80=0

We move all terms containing y to the left, all other terms to the right

190y=80

y=80/190

y=8/19

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