10(2a+3)-4(a-2)=134

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Solution for 10(2a+3)-4(a-2)=134 equation:



10(2a+3)-4(a-2)=134
We move all terms to the left:
10(2a+3)-4(a-2)-(134)=0
We multiply parentheses
20a-4a+30+8-134=0
We add all the numbers together, and all the variables
16a-96=0
We move all terms containing a to the left, all other terms to the right
16a=96
a=96/16
a=6

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