10(2b-1)=5(b-1)

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Solution for 10(2b-1)=5(b-1) equation: 



10(2b-1)=5(b-1)

We move all terms to the left:

10(2b-1)-(5(b-1))=0

We multiply parentheses

20b-(5(b-1))-10=0



We calculate terms in parentheses: -(5(b-1)), so:

5(b-1)

We multiply parentheses

5b-5

Back to the equation:

-(5b-5)



We get rid of parentheses

20b-5b+5-10=0

We add all the numbers together, and all the variables

15b-5=0

We move all terms containing b to the left, all other terms to the right

15b=5

b=5/15

b=1/3

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