10(2m-6)=6(3m+10)-15

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Solution for 10(2m-6)=6(3m+10)-15 equation: 



10(2m-6)=6(3m+10)-15

We move all terms to the left:

10(2m-6)-(6(3m+10)-15)=0

We multiply parentheses

20m-(6(3m+10)-15)-60=0



We calculate terms in parentheses: -(6(3m+10)-15), so:

6(3m+10)-15

We multiply parentheses

18m+60-15

We add all the numbers together, and all the variables

18m+45

Back to the equation:

-(18m+45)



We get rid of parentheses

20m-18m-45-60=0

We add all the numbers together, and all the variables

2m-105=0

We move all terms containing m to the left, all other terms to the right

2m=105

m=105/2

m=52+1/2

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