10(2p+2)-p=2(8p-8)

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Solution for 10(2p+2)-p=2(8p-8) equation: 



10(2p+2)-p=2(8p-8)

We move all terms to the left:

10(2p+2)-p-(2(8p-8))=0

We add all the numbers together, and all the variables

-1p+10(2p+2)-(2(8p-8))=0

We multiply parentheses

-1p+20p-(2(8p-8))+20=0



We calculate terms in parentheses: -(2(8p-8)), so:

2(8p-8)

We multiply parentheses

16p-16

Back to the equation:

-(16p-16)



We add all the numbers together, and all the variables

19p-(16p-16)+20=0

We get rid of parentheses

19p-16p+16+20=0

We add all the numbers together, and all the variables

3p+36=0

We move all terms containing p to the left, all other terms to the right

3p=-36

p=-36/3

p=-12

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