10(2t+2)-t=2(8t-8)

Solution for 10(2t+2)-t=2(8t-8) equation:

10(2t+2)-t=2(8t-8)

We move all terms to the left:

10(2t+2)-t-(2(8t-8))=0

We add all the numbers together, and all the variables

-1t+10(2t+2)-(2(8t-8))=0

We multiply parentheses

-1t+20t-(2(8t-8))+20=0


We calculate terms in parentheses: -(2(8t-8)), so:

2(8t-8)

We multiply parentheses

16t-16

Back to the equation:

-(16t-16)


We add all the numbers together, and all the variables

19t-(16t-16)+20=0

We get rid of parentheses

19t-16t+16+20=0

We add all the numbers together, and all the variables

3t+36=0

We move all terms containing t to the left, all other terms to the right

3t=-36

t=-36/3

t=-12