10(2x+1)-6=12(x+1)+8(x-2)

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Solution for 10(2x+1)-6=12(x+1)+8(x-2) equation:


Simplifying
10(2x + 1) + -6 = 12(x + 1) + 8(x + -2)

Reorder the terms:
10(1 + 2x) + -6 = 12(x + 1) + 8(x + -2)
(1 * 10 + 2x * 10) + -6 = 12(x + 1) + 8(x + -2)
(10 + 20x) + -6 = 12(x + 1) + 8(x + -2)

Reorder the terms:
10 + -6 + 20x = 12(x + 1) + 8(x + -2)

Combine like terms: 10 + -6 = 4
4 + 20x = 12(x + 1) + 8(x + -2)

Reorder the terms:
4 + 20x = 12(1 + x) + 8(x + -2)
4 + 20x = (1 * 12 + x * 12) + 8(x + -2)
4 + 20x = (12 + 12x) + 8(x + -2)

Reorder the terms:
4 + 20x = 12 + 12x + 8(-2 + x)
4 + 20x = 12 + 12x + (-2 * 8 + x * 8)
4 + 20x = 12 + 12x + (-16 + 8x)

Reorder the terms:
4 + 20x = 12 + -16 + 12x + 8x

Combine like terms: 12 + -16 = -4
4 + 20x = -4 + 12x + 8x

Combine like terms: 12x + 8x = 20x
4 + 20x = -4 + 20x

Add '-20x' to each side of the equation.
4 + 20x + -20x = -4 + 20x + -20x

Combine like terms: 20x + -20x = 0
4 + 0 = -4 + 20x + -20x
4 = -4 + 20x + -20x

Combine like terms: 20x + -20x = 0
4 = -4 + 0
4 = -4

Solving
4 = -4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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