10(2x+15)-15(x+10)=9(10-x)+100(x+12)

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Solution for 10(2x+15)-15(x+10)=9(10-x)+100(x+12) equation: 



10(2x+15)-15(x+10)=9(10-x)+100(x+12)

We move all terms to the left:

10(2x+15)-15(x+10)-(9(10-x)+100(x+12))=0

We add all the numbers together, and all the variables

10(2x+15)-15(x+10)-(9(-1x+10)+100(x+12))=0

We multiply parentheses

20x-15x-(9(-1x+10)+100(x+12))+150-150=0



We calculate terms in parentheses: -(9(-1x+10)+100(x+12)), so:

9(-1x+10)+100(x+12)

We multiply parentheses

-9x+100x+90+1200

We add all the numbers together, and all the variables

91x+1290

Back to the equation:

-(91x+1290)



We add all the numbers together, and all the variables

5x-(91x+1290)=0

We get rid of parentheses

5x-91x-1290=0

We add all the numbers together, and all the variables

-86x-1290=0

We move all terms containing x to the left, all other terms to the right

-86x=1290

x=1290/-86

x=-15

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