10(2x+2)-1x=2(8x-8)

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Solution for 10(2x+2)-1x=2(8x-8) equation: 



10(2x+2)-1x=2(8x-8)

We move all terms to the left:

10(2x+2)-1x-(2(8x-8))=0

We add all the numbers together, and all the variables

-1x+10(2x+2)-(2(8x-8))=0

We multiply parentheses

-1x+20x-(2(8x-8))+20=0



We calculate terms in parentheses: -(2(8x-8)), so:

2(8x-8)

We multiply parentheses

16x-16

Back to the equation:

-(16x-16)



We add all the numbers together, and all the variables

19x-(16x-16)+20=0

We get rid of parentheses

19x-16x+16+20=0

We add all the numbers together, and all the variables

3x+36=0

We move all terms containing x to the left, all other terms to the right

3x=-36

x=-36/3

x=-12

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