10(2x+2)-x=2(8x+8)

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Solution for 10(2x+2)-x=2(8x+8) equation: 



10(2x+2)-x=2(8x+8)

We move all terms to the left:

10(2x+2)-x-(2(8x+8))=0

We add all the numbers together, and all the variables

-1x+10(2x+2)-(2(8x+8))=0

We multiply parentheses

-1x+20x-(2(8x+8))+20=0



We calculate terms in parentheses: -(2(8x+8)), so:

2(8x+8)

We multiply parentheses

16x+16

Back to the equation:

-(16x+16)



We add all the numbers together, and all the variables

19x-(16x+16)+20=0

We get rid of parentheses

19x-16x-16+20=0

We add all the numbers together, and all the variables

3x+4=0

We move all terms containing x to the left, all other terms to the right

3x=-4

x=-4/3

x=-1+1/3

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