10(2x+2)=6(3x+8)

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Solution for 10(2x+2)=6(3x+8) equation: 



10(2x+2)=6(3x+8)

We move all terms to the left:

10(2x+2)-(6(3x+8))=0

We multiply parentheses

20x-(6(3x+8))+20=0



We calculate terms in parentheses: -(6(3x+8)), so:

6(3x+8)

We multiply parentheses

18x+48

Back to the equation:

-(18x+48)



We get rid of parentheses

20x-18x-48+20=0

We add all the numbers together, and all the variables

2x-28=0

We move all terms containing x to the left, all other terms to the right

2x=28

x=28/2

x=14

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