10(2x+2x)-x=2(8x-8)

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Solution for 10(2x+2x)-x=2(8x-8) equation: 



10(2x+2x)-x=2(8x-8)

We move all terms to the left:

10(2x+2x)-x-(2(8x-8))=0

We add all the numbers together, and all the variables

10(+4x)-x-(2(8x-8))=0

We add all the numbers together, and all the variables

-1x+10(+4x)-(2(8x-8))=0

We multiply parentheses

-1x+40x-(2(8x-8))=0



We calculate terms in parentheses: -(2(8x-8)), so:

2(8x-8)

We multiply parentheses

16x-16

Back to the equation:

-(16x-16)



We add all the numbers together, and all the variables

39x-(16x-16)=0

We get rid of parentheses

39x-16x+16=0

We add all the numbers together, and all the variables

23x+16=0

We move all terms containing x to the left, all other terms to the right

23x=-16

x=-16/23

x=-16/23

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