10(2x+3)=7(3x+4)

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Solution for 10(2x+3)=7(3x+4) equation: 



10(2x+3)=7(3x+4)

We move all terms to the left:

10(2x+3)-(7(3x+4))=0

We multiply parentheses

20x-(7(3x+4))+30=0



We calculate terms in parentheses: -(7(3x+4)), so:

7(3x+4)

We multiply parentheses

21x+28

Back to the equation:

-(21x+28)



We get rid of parentheses

20x-21x-28+30=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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