10(2x-1)=6(2x+1)+16

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Solution for 10(2x-1)=6(2x+1)+16 equation: 



10(2x-1)=6(2x+1)+16

We move all terms to the left:

10(2x-1)-(6(2x+1)+16)=0

We multiply parentheses

20x-(6(2x+1)+16)-10=0



We calculate terms in parentheses: -(6(2x+1)+16), so:

6(2x+1)+16

We multiply parentheses

12x+6+16

We add all the numbers together, and all the variables

12x+22

Back to the equation:

-(12x+22)



We get rid of parentheses

20x-12x-22-10=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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