10(2x-1)=8(2x+1)+4x

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Solution for 10(2x-1)=8(2x+1)+4x equation: 



10(2x-1)=8(2x+1)+4x

We move all terms to the left:

10(2x-1)-(8(2x+1)+4x)=0

We multiply parentheses

20x-(8(2x+1)+4x)-10=0



We calculate terms in parentheses: -(8(2x+1)+4x), so:

8(2x+1)+4x

We add all the numbers together, and all the variables

4x+8(2x+1)

We multiply parentheses

4x+16x+8

We add all the numbers together, and all the variables

20x+8

Back to the equation:

-(20x+8)



We get rid of parentheses

20x-20x-8-10=0

We add all the numbers together, and all the variables

-18!=0

There is no solution for this equation

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