10(2x-1)=8(2x+1)+4x-18

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Solution for 10(2x-1)=8(2x+1)+4x-18 equation: 



10(2x-1)=8(2x+1)+4x-18

We move all terms to the left:

10(2x-1)-(8(2x+1)+4x-18)=0

We multiply parentheses

20x-(8(2x+1)+4x-18)-10=0



We calculate terms in parentheses: -(8(2x+1)+4x-18), so:

8(2x+1)+4x-18

We add all the numbers together, and all the variables

4x+8(2x+1)-18

We multiply parentheses

4x+16x+8-18

We add all the numbers together, and all the variables

20x-10

Back to the equation:

-(20x-10)



We get rid of parentheses

20x-20x+10-10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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