10(2x-2)-x=2(8x-8)

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Solution for 10(2x-2)-x=2(8x-8) equation:



10(2x-2)-x=2(8x-8)
We move all terms to the left:
10(2x-2)-x-(2(8x-8))=0
We add all the numbers together, and all the variables
-1x+10(2x-2)-(2(8x-8))=0
We multiply parentheses
-1x+20x-(2(8x-8))-20=0
We calculate terms in parentheses: -(2(8x-8)), so:
2(8x-8)
We multiply parentheses
16x-16
Back to the equation:
-(16x-16)
We add all the numbers together, and all the variables
19x-(16x-16)-20=0
We get rid of parentheses
19x-16x+16-20=0
We add all the numbers together, and all the variables
3x-4=0
We move all terms containing x to the left, all other terms to the right
3x=4
x=4/3
x=1+1/3

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