10(2x-3)=4(2x+8)

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Solution for 10(2x-3)=4(2x+8) equation: 



10(2x-3)=4(2x+8)

We move all terms to the left:

10(2x-3)-(4(2x+8))=0

We multiply parentheses

20x-(4(2x+8))-30=0



We calculate terms in parentheses: -(4(2x+8)), so:

4(2x+8)

We multiply parentheses

8x+32

Back to the equation:

-(8x+32)



We get rid of parentheses

20x-8x-32-30=0

We add all the numbers together, and all the variables

12x-62=0

We move all terms containing x to the left, all other terms to the right

12x=62

x=62/12

x=5+1/6

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