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10(2x-3)=5(x+6)
We move all terms to the left:
10(2x-3)-(5(x+6))=0
We multiply parentheses
20x-(5(x+6))-30=0
We calculate terms in parentheses: -(5(x+6)), so:We get rid of parentheses
5(x+6)
We multiply parentheses
5x+30
Back to the equation:
-(5x+30)
20x-5x-30-30=0
We add all the numbers together, and all the variables
15x-60=0
We move all terms containing x to the left, all other terms to the right
15x=60
x=60/15
x=4
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