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10(2x-4)=-(-8-9x)+3x
We move all terms to the left:
10(2x-4)-(-(-8-9x)+3x)=0
We add all the numbers together, and all the variables
10(2x-4)-(-(-9x-8)+3x)=0
We multiply parentheses
20x-(-(-9x-8)+3x)-40=0
We calculate terms in parentheses: -(-(-9x-8)+3x), so:We get rid of parentheses
-(-9x-8)+3x
We add all the numbers together, and all the variables
3x-(-9x-8)
We get rid of parentheses
3x+9x+8
We add all the numbers together, and all the variables
12x+8
Back to the equation:
-(12x+8)
20x-12x-8-40=0
We add all the numbers together, and all the variables
8x-48=0
We move all terms containing x to the left, all other terms to the right
8x=48
x=48/8
x=6
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