10(2x-4)=-(-8-9x)+3x

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Solution for 10(2x-4)=-(-8-9x)+3x equation: 



10(2x-4)=-(-8-9x)+3x

We move all terms to the left:

10(2x-4)-(-(-8-9x)+3x)=0

We add all the numbers together, and all the variables

10(2x-4)-(-(-9x-8)+3x)=0

We multiply parentheses

20x-(-(-9x-8)+3x)-40=0



We calculate terms in parentheses: -(-(-9x-8)+3x), so:

-(-9x-8)+3x

We add all the numbers together, and all the variables

3x-(-9x-8)

We get rid of parentheses

3x+9x+8

We add all the numbers together, and all the variables

12x+8

Back to the equation:

-(12x+8)



We get rid of parentheses

20x-12x-8-40=0

We add all the numbers together, and all the variables

8x-48=0

We move all terms containing x to the left, all other terms to the right

8x=48

x=48/8

x=6

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