10(2x-5)-3=10(x-4)+(7)

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Solution for 10(2x-5)-3=10(x-4)+(7) equation: 



10(2x-5)-3=10(x-4)+(7)

We move all terms to the left:

10(2x-5)-3-(10(x-4)+(7))=0

We multiply parentheses

20x-(10(x-4)+7)-50-3=0



We calculate terms in parentheses: -(10(x-4)+7), so:

10(x-4)+7

We multiply parentheses

10x-40+7

We add all the numbers together, and all the variables

10x-33

Back to the equation:

-(10x-33)



We add all the numbers together, and all the variables

20x-(10x-33)-53=0

We get rid of parentheses

20x-10x+33-53=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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