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10(2x-5)=2x+2(x+1)
We move all terms to the left:
10(2x-5)-(2x+2(x+1))=0
We multiply parentheses
20x-(2x+2(x+1))-50=0
We calculate terms in parentheses: -(2x+2(x+1)), so:We get rid of parentheses
2x+2(x+1)
We multiply parentheses
2x+2x+2
We add all the numbers together, and all the variables
4x+2
Back to the equation:
-(4x+2)
20x-4x-2-50=0
We add all the numbers together, and all the variables
16x-52=0
We move all terms containing x to the left, all other terms to the right
16x=52
x=52/16
x=3+1/4
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