10(2y+2)*y=2(8y-8)

Solution for 10(2y+2)*y=2(8y-8) equation:

10(2y+2)*y=2(8y-8)

We move all terms to the left:

10(2y+2)*y-(2(8y-8))=0

We multiply parentheses

20y^2+20y-(2(8y-8))=0


We calculate terms in parentheses: -(2(8y-8)), so:

2(8y-8)

We multiply parentheses

16y-16

Back to the equation:

-(16y-16)


We get rid of parentheses

20y^2+20y-16y+16=0

We add all the numbers together, and all the variables

20y^2+4y+16=0

a = 20; b = 4; c = +16;
Δ = b2-4ac
Δ = 42-4·20·16
Δ = -1264
Delta is less than zero, so there is no solution for the equation