10(2y+2)-1=2(8y-8)

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Solution for 10(2y+2)-1=2(8y-8) equation: 



10(2y+2)-1=2(8y-8)

We move all terms to the left:

10(2y+2)-1-(2(8y-8))=0

We multiply parentheses

20y-(2(8y-8))+20-1=0



We calculate terms in parentheses: -(2(8y-8)), so:

2(8y-8)

We multiply parentheses

16y-16

Back to the equation:

-(16y-16)



We add all the numbers together, and all the variables

20y-(16y-16)+19=0

We get rid of parentheses

20y-16y+16+19=0

We add all the numbers together, and all the variables

4y+35=0

We move all terms containing y to the left, all other terms to the right

4y=-35

y=-35/4

y=-8+3/4

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