10(2y+2)-9=Y2(8y-8)

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Solution for 10(2y+2)-9=Y2(8y-8) equation: 



10(2y+2)-9=2(8y-8)

We move all terms to the left:

10(2y+2)-9-(2(8y-8))=0

We multiply parentheses

20y-(2(8y-8))+20-9=0



We calculate terms in parentheses: -(2(8y-8)), so:

2(8y-8)

We multiply parentheses

16y-16

Back to the equation:

-(16y-16)



We add all the numbers together, and all the variables

20y-(16y-16)+11=0

We get rid of parentheses

20y-16y+16+11=0

We add all the numbers together, and all the variables

4y+27=0

We move all terms containing y to the left, all other terms to the right

4y=-27

y=-27/4

y=-6+3/4

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