10(2y+2)-y=2(8y+8)

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Solution for 10(2y+2)-y=2(8y+8) equation: 



10(2y+2)-y=2(8y+8)

We move all terms to the left:

10(2y+2)-y-(2(8y+8))=0

We add all the numbers together, and all the variables

-1y+10(2y+2)-(2(8y+8))=0

We multiply parentheses

-1y+20y-(2(8y+8))+20=0



We calculate terms in parentheses: -(2(8y+8)), so:

2(8y+8)

We multiply parentheses

16y+16

Back to the equation:

-(16y+16)



We add all the numbers together, and all the variables

19y-(16y+16)+20=0

We get rid of parentheses

19y-16y-16+20=0

We add all the numbers together, and all the variables

3y+4=0

We move all terms containing y to the left, all other terms to the right

3y=-4

y=-4/3

y=-1+1/3

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