10(2y+2)-y=2(8y-5)

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Solution for 10(2y+2)-y=2(8y-5) equation: 



10(2y+2)-y=2(8y-5)

We move all terms to the left:

10(2y+2)-y-(2(8y-5))=0

We add all the numbers together, and all the variables

-1y+10(2y+2)-(2(8y-5))=0

We multiply parentheses

-1y+20y-(2(8y-5))+20=0



We calculate terms in parentheses: -(2(8y-5)), so:

2(8y-5)

We multiply parentheses

16y-10

Back to the equation:

-(16y-10)



We add all the numbers together, and all the variables

19y-(16y-10)+20=0

We get rid of parentheses

19y-16y+10+20=0

We add all the numbers together, and all the variables

3y+30=0

We move all terms containing y to the left, all other terms to the right

3y=-30

y=-30/3

y=-10

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