10(2y+2)-y=22(8y+8)

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Solution for 10(2y+2)-y=22(8y+8) equation: 



10(2y+2)-y=22(8y+8)

We move all terms to the left:

10(2y+2)-y-(22(8y+8))=0

We add all the numbers together, and all the variables

-1y+10(2y+2)-(22(8y+8))=0

We multiply parentheses

-1y+20y-(22(8y+8))+20=0



We calculate terms in parentheses: -(22(8y+8)), so:

22(8y+8)

We multiply parentheses

176y+176

Back to the equation:

-(176y+176)



We add all the numbers together, and all the variables

19y-(176y+176)+20=0

We get rid of parentheses

19y-176y-176+20=0

We add all the numbers together, and all the variables

-157y-156=0

We move all terms containing y to the left, all other terms to the right

-157y=156

y=156/-157

y=-156/157

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