10(2y+2)=-y=2(8y-8)

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Solution for 10(2y+2)=-y=2(8y-8) equation: 



10(2y+2)=-y=2(8y-8)

We move all terms to the left:

10(2y+2)-(-y)=0

We add all the numbers together, and all the variables

10(2y+2)-(-1y)=0

We multiply parentheses

20y-(-1y)+20=0

We get rid of parentheses

20y+1y+20=0

We add all the numbers together, and all the variables

21y+20=0

We move all terms containing y to the left, all other terms to the right

21y=-20

y=-20/21

y=-20/21

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