10(2y+2)=4y-12(y-1)

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Solution for 10(2y+2)=4y-12(y-1) equation: 



10(2y+2)=4y-12(y-1)

We move all terms to the left:

10(2y+2)-(4y-12(y-1))=0

We multiply parentheses

20y-(4y-12(y-1))+20=0



We calculate terms in parentheses: -(4y-12(y-1)), so:

4y-12(y-1)

We multiply parentheses

4y-12y+12

We add all the numbers together, and all the variables

-8y+12

Back to the equation:

-(-8y+12)



We get rid of parentheses

20y+8y-12+20=0

We add all the numbers together, and all the variables

28y+8=0

We move all terms containing y to the left, all other terms to the right

28y=-8

y=-8/28

y=-2/7

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