10(2y+2y)-y=2(8y-8)

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Solution for 10(2y+2y)-y=2(8y-8) equation: 



10(2y+2y)-y=2(8y-8)

We move all terms to the left:

10(2y+2y)-y-(2(8y-8))=0

We add all the numbers together, and all the variables

10(+4y)-y-(2(8y-8))=0

We add all the numbers together, and all the variables

-1y+10(+4y)-(2(8y-8))=0

We multiply parentheses

-1y+40y-(2(8y-8))=0



We calculate terms in parentheses: -(2(8y-8)), so:

2(8y-8)

We multiply parentheses

16y-16

Back to the equation:

-(16y-16)



We add all the numbers together, and all the variables

39y-(16y-16)=0

We get rid of parentheses

39y-16y+16=0

We add all the numbers together, and all the variables

23y+16=0

We move all terms containing y to the left, all other terms to the right

23y=-16

y=-16/23

y=-16/23

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