10(2y+3)-y=298y-8)

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Solution for 10(2y+3)-y=298y-8) equation: 



10(2y+3)-y=298y-8)

We move all terms to the left:

10(2y+3)-y-(298y-8))=0

We add all the numbers together, and all the variables

-1y+10(2y+3)-(298y-8))=0

We multiply parentheses

-1y+20y-(298y-8))+30=0

We add all the numbers together, and all the variables

19y-(298y-8))+30=0

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