10(2y+3)-y=3(8y-8)

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Solution for 10(2y+3)-y=3(8y-8) equation: 



10(2y+3)-y=3(8y-8)

We move all terms to the left:

10(2y+3)-y-(3(8y-8))=0

We add all the numbers together, and all the variables

-1y+10(2y+3)-(3(8y-8))=0

We multiply parentheses

-1y+20y-(3(8y-8))+30=0



We calculate terms in parentheses: -(3(8y-8)), so:

3(8y-8)

We multiply parentheses

24y-24

Back to the equation:

-(24y-24)



We add all the numbers together, and all the variables

19y-(24y-24)+30=0

We get rid of parentheses

19y-24y+24+30=0

We add all the numbers together, and all the variables

-5y+54=0

We move all terms containing y to the left, all other terms to the right

-5y=-54

y=-54/-5

y=10+4/5

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