10(2y+3)=5(4y+6)

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Solution for 10(2y+3)=5(4y+6) equation: 



10(2y+3)=5(4y+6)

We move all terms to the left:

10(2y+3)-(5(4y+6))=0

We multiply parentheses

20y-(5(4y+6))+30=0



We calculate terms in parentheses: -(5(4y+6)), so:

5(4y+6)

We multiply parentheses

20y+30

Back to the equation:

-(20y+30)



We get rid of parentheses

20y-20y-30+30=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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