10(2y-2)=3y-3

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Solution for 10(2y-2)=3y-3 equation: 



10(2y-2)=3y-3

We move all terms to the left:

10(2y-2)-(3y-3)=0

We multiply parentheses

20y-(3y-3)-20=0

We get rid of parentheses

20y-3y+3-20=0

We add all the numbers together, and all the variables

17y-17=0

We move all terms containing y to the left, all other terms to the right

17y=17

y=17/17

y=1

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