10(2y-4)=(6-9y)+3y

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Solution for 10(2y-4)=(6-9y)+3y equation: 



10(2y-4)=(6-9y)+3y

We move all terms to the left:

10(2y-4)-((6-9y)+3y)=0

We add all the numbers together, and all the variables

10(2y-4)-((-9y+6)+3y)=0

We multiply parentheses

20y-((-9y+6)+3y)-40=0



We calculate terms in parentheses: -((-9y+6)+3y), so:

(-9y+6)+3y

We add all the numbers together, and all the variables

3y+(-9y+6)

We get rid of parentheses

3y-9y+6

We add all the numbers together, and all the variables

-6y+6

Back to the equation:

-(-6y+6)



We get rid of parentheses

20y+6y-6-40=0

We add all the numbers together, and all the variables

26y-46=0

We move all terms containing y to the left, all other terms to the right

26y=46

y=46/26

y=1+10/13

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