10(2z+3)-3(3z-6)=48

Solution for 10(2z+3)-3(3z-6)=48 equation:

Simplifying
10(2z + 3) + -3(3z + -6) = 48

Reorder the terms:
10(3 + 2z) + -3(3z + -6) = 48
(3 * 10 + 2z * 10) + -3(3z + -6) = 48
(30 + 20z) + -3(3z + -6) = 48

Reorder the terms:
30 + 20z + -3(-6 + 3z) = 48
30 + 20z + (-6 * -3 + 3z * -3) = 48
30 + 20z + (18 + -9z) = 48

Reorder the terms:
30 + 18 + 20z + -9z = 48

Combine like terms: 30 + 18 = 48
48 + 20z + -9z = 48

Combine like terms: 20z + -9z = 11z
48 + 11z = 48

Add '-48' to each side of the equation.
48 + -48 + 11z = 48 + -48

Combine like terms: 48 + -48 = 0
0 + 11z = 48 + -48
11z = 48 + -48

Combine like terms: 48 + -48 = 0
11z = 0

Solving
11z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Divide each side by '11'.
z = 0

Simplifying
z = 0