10(3+b)=3b-4

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Solution for 10(3+b)=3b-4 equation: 



10(3+b)=3b-4

We move all terms to the left:

10(3+b)-(3b-4)=0

We add all the numbers together, and all the variables

10(b+3)-(3b-4)=0

We multiply parentheses

10b-(3b-4)+30=0

We get rid of parentheses

10b-3b+4+30=0

We add all the numbers together, and all the variables

7b+34=0

We move all terms containing b to the left, all other terms to the right

7b=-34

b=-34/7

b=-4+6/7

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